Algebra Practice Test 2026 – Complete Exam Preparation

Question: 1 / 400

If x² = 16, what are the possible values of x?

x = 4 or x = -4

To determine the possible values of \( x \) from the equation \( x² = 16 \), we need to isolate \( x \). Taking the square root of both sides of the equation gives us \( x = \sqrt{16} \) or \( x = -\sqrt{16} \).

Calculating the square root of 16 gives us 4, so the two possible solutions are \( x = 4 \) and \( x = -4 \). This reflects the property of square roots that both the positive and negative values satisfy the original equation since squaring either results in a positive value, which is 16 in this case.

Thus, the correct answer, with the values of \( x \) being 4 and -4, highlights the fact that both answers satisfy the condition \( x² = 16 \). This understanding reinforces the principle that equations involving squares can lead to two distinct solutions due to their symmetrical nature on the number line.

Get further explanation with Examzify DeepDiveBeta

x = 8 or x = -8

x = 0 or x = 16

x = 2 or x = -2

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